-(2^x)=3/4x

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Solution for -(2^x)=3/4x equation:



-(2^x)=3/4x
We move all terms to the left:
-(2^x)-(3/4x)=0
Domain of the equation: 4x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
-2^x-(+3/4x)=0
We get rid of parentheses
-2^x-3/4x=0
We multiply all the terms by the denominator
-2^x*4x-3=0
Wy multiply elements
-8x^2-3=0
a = -8; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·(-8)·(-3)
Δ = -96
Delta is less than zero, so there is no solution for the equation

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